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Formulae for Maximum Bending Moments and Shears in Gantry Girders |
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The formulae given assume the following conditions:- L = Span of Gantry Girder (adjacent girders are of equal span and are assumed to be simply supported). C = Centres of end carriage wheels (two wheels are assumed for each end carriage, and where two cranes occur they are assumed to be identical in all respects). G = The minimum centres between adjacent wheels of two end carriages (only applicable when two cranes are considered and when G < C ). Mx = Maximum Bending Moment in the Gantry Girder, for the crane configuration shown. Fv = Maximum Shear Force in the Gantry Girder, for the condition stated. W = The loading from one wheel. (all wheels are assumed to have the same load). |
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Gantry Girder Formulae |
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Loading Configuration |
Maximum Moment |
Maximum Shear |
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C > 0.5858.L |
x = L/2 Mx = W.L/4 |
x = 0 If C < L then Fv = W/L(2.L - C) If C > L then Fv = W |
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C < 0.5858.L |
x = L/2 - C/4 Mx = 2.W.x2/L |
x = 0 Fv = W/L(2.L - C) |
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G < 0.5858.L |
x = L/2 - G/4 Mx = 2.W.x2/L |
x = 0 Fv = W/L(2.L - G) |
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x = L/2 + C/6 - G/6 Mx = 3.W. x2/L - W.C |
x = 0 Fv = W/L(3.L - 2.G - C) |
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x = L/2 - G/4 Mx = 4.W. x2/L - W.C |
x = C Fv = W/L(4.L - 4.C - 2.G) |
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Notes 1. All possible crane configurations should be checked to determine the maximum force in the gantry girder. |
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Document (No. 20020120/WS/001) |
MG Double © 1970 - 2002 |
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